Optimal. Leaf size=432 \[ \frac {\left (-2 \sqrt {a} \sqrt {a+b}+a+b\right ) \log \left (-\sqrt {2} \sqrt [4]{a} x \sqrt {\sqrt {a+b}-\sqrt {a}}+\sqrt {a+b}+\sqrt {a} x^2\right )}{4 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {\sqrt {a+b}-\sqrt {a}}}-\frac {\left (-2 \sqrt {a} \sqrt {a+b}+a+b\right ) \log \left (\sqrt {2} \sqrt [4]{a} x \sqrt {\sqrt {a+b}-\sqrt {a}}+\sqrt {a+b}+\sqrt {a} x^2\right )}{4 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {\sqrt {a+b}-\sqrt {a}}}+\frac {\left (2 \sqrt {a} \sqrt {a+b}+a+b\right ) \tan ^{-1}\left (\frac {\sqrt {\sqrt {a+b}-\sqrt {a}}-\sqrt {2} \sqrt [4]{a} x}{\sqrt {\sqrt {a+b}+\sqrt {a}}}\right )}{2 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {\sqrt {a+b}+\sqrt {a}}}-\frac {\left (2 \sqrt {a} \sqrt {a+b}+a+b\right ) \tan ^{-1}\left (\frac {\sqrt {\sqrt {a+b}-\sqrt {a}}+\sqrt {2} \sqrt [4]{a} x}{\sqrt {\sqrt {a+b}+\sqrt {a}}}\right )}{2 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {\sqrt {a+b}+\sqrt {a}}}+\frac {x}{a} \]
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Rubi [A] time = 0.89, antiderivative size = 432, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 6, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {1122, 1169, 634, 618, 204, 628} \begin {gather*} \frac {\left (-2 \sqrt {a} \sqrt {a+b}+a+b\right ) \log \left (-\sqrt {2} \sqrt [4]{a} x \sqrt {\sqrt {a+b}-\sqrt {a}}+\sqrt {a+b}+\sqrt {a} x^2\right )}{4 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {\sqrt {a+b}-\sqrt {a}}}-\frac {\left (-2 \sqrt {a} \sqrt {a+b}+a+b\right ) \log \left (\sqrt {2} \sqrt [4]{a} x \sqrt {\sqrt {a+b}-\sqrt {a}}+\sqrt {a+b}+\sqrt {a} x^2\right )}{4 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {\sqrt {a+b}-\sqrt {a}}}+\frac {\left (2 \sqrt {a} \sqrt {a+b}+a+b\right ) \tan ^{-1}\left (\frac {\sqrt {\sqrt {a+b}-\sqrt {a}}-\sqrt {2} \sqrt [4]{a} x}{\sqrt {\sqrt {a+b}+\sqrt {a}}}\right )}{2 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {\sqrt {a+b}+\sqrt {a}}}-\frac {\left (2 \sqrt {a} \sqrt {a+b}+a+b\right ) \tan ^{-1}\left (\frac {\sqrt {\sqrt {a+b}-\sqrt {a}}+\sqrt {2} \sqrt [4]{a} x}{\sqrt {\sqrt {a+b}+\sqrt {a}}}\right )}{2 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {\sqrt {a+b}+\sqrt {a}}}+\frac {x}{a} \end {gather*}
Antiderivative was successfully verified.
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Rule 204
Rule 618
Rule 628
Rule 634
Rule 1122
Rule 1169
Rubi steps
\begin {align*} \int \frac {x^4}{a+b+2 a x^2+a x^4} \, dx &=\frac {x}{a}-\frac {\int \frac {a+b+2 a x^2}{a+b+2 a x^2+a x^4} \, dx}{a}\\ &=\frac {x}{a}-\frac {\int \frac {\frac {\sqrt {2} (a+b) \sqrt {-\sqrt {a}+\sqrt {a+b}}}{\sqrt [4]{a}}-\left (a+b-2 \sqrt {a} \sqrt {a+b}\right ) x}{\frac {\sqrt {a+b}}{\sqrt {a}}-\frac {\sqrt {2} \sqrt {-\sqrt {a}+\sqrt {a+b}} x}{\sqrt [4]{a}}+x^2} \, dx}{2 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {-\sqrt {a}+\sqrt {a+b}}}-\frac {\int \frac {\frac {\sqrt {2} (a+b) \sqrt {-\sqrt {a}+\sqrt {a+b}}}{\sqrt [4]{a}}+\left (a+b-2 \sqrt {a} \sqrt {a+b}\right ) x}{\frac {\sqrt {a+b}}{\sqrt {a}}+\frac {\sqrt {2} \sqrt {-\sqrt {a}+\sqrt {a+b}} x}{\sqrt [4]{a}}+x^2} \, dx}{2 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {-\sqrt {a}+\sqrt {a+b}}}\\ &=\frac {x}{a}+\frac {\left (a+b-2 \sqrt {a} \sqrt {a+b}\right ) \int \frac {-\frac {\sqrt {2} \sqrt {-\sqrt {a}+\sqrt {a+b}}}{\sqrt [4]{a}}+2 x}{\frac {\sqrt {a+b}}{\sqrt {a}}-\frac {\sqrt {2} \sqrt {-\sqrt {a}+\sqrt {a+b}} x}{\sqrt [4]{a}}+x^2} \, dx}{4 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {-\sqrt {a}+\sqrt {a+b}}}-\frac {\left (a+b-2 \sqrt {a} \sqrt {a+b}\right ) \int \frac {\frac {\sqrt {2} \sqrt {-\sqrt {a}+\sqrt {a+b}}}{\sqrt [4]{a}}+2 x}{\frac {\sqrt {a+b}}{\sqrt {a}}+\frac {\sqrt {2} \sqrt {-\sqrt {a}+\sqrt {a+b}} x}{\sqrt [4]{a}}+x^2} \, dx}{4 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {-\sqrt {a}+\sqrt {a+b}}}-\frac {\left (a+b+2 \sqrt {a} \sqrt {a+b}\right ) \int \frac {1}{\frac {\sqrt {a+b}}{\sqrt {a}}-\frac {\sqrt {2} \sqrt {-\sqrt {a}+\sqrt {a+b}} x}{\sqrt [4]{a}}+x^2} \, dx}{4 a^{3/2} \sqrt {a+b}}-\frac {\left (a+b+2 \sqrt {a} \sqrt {a+b}\right ) \int \frac {1}{\frac {\sqrt {a+b}}{\sqrt {a}}+\frac {\sqrt {2} \sqrt {-\sqrt {a}+\sqrt {a+b}} x}{\sqrt [4]{a}}+x^2} \, dx}{4 a^{3/2} \sqrt {a+b}}\\ &=\frac {x}{a}+\frac {\left (a+b-2 \sqrt {a} \sqrt {a+b}\right ) \log \left (\sqrt {a+b}-\sqrt {2} \sqrt [4]{a} \sqrt {-\sqrt {a}+\sqrt {a+b}} x+\sqrt {a} x^2\right )}{4 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {-\sqrt {a}+\sqrt {a+b}}}-\frac {\left (a+b-2 \sqrt {a} \sqrt {a+b}\right ) \log \left (\sqrt {a+b}+\sqrt {2} \sqrt [4]{a} \sqrt {-\sqrt {a}+\sqrt {a+b}} x+\sqrt {a} x^2\right )}{4 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {-\sqrt {a}+\sqrt {a+b}}}+\frac {\left (a+b+2 \sqrt {a} \sqrt {a+b}\right ) \operatorname {Subst}\left (\int \frac {1}{-2 \left (1+\frac {\sqrt {a+b}}{\sqrt {a}}\right )-x^2} \, dx,x,-\frac {\sqrt {2} \sqrt {-\sqrt {a}+\sqrt {a+b}}}{\sqrt [4]{a}}+2 x\right )}{2 a^{3/2} \sqrt {a+b}}+\frac {\left (a+b+2 \sqrt {a} \sqrt {a+b}\right ) \operatorname {Subst}\left (\int \frac {1}{-2 \left (1+\frac {\sqrt {a+b}}{\sqrt {a}}\right )-x^2} \, dx,x,\frac {\sqrt {2} \sqrt {-\sqrt {a}+\sqrt {a+b}}}{\sqrt [4]{a}}+2 x\right )}{2 a^{3/2} \sqrt {a+b}}\\ &=\frac {x}{a}+\frac {\left (a+b+2 \sqrt {a} \sqrt {a+b}\right ) \tan ^{-1}\left (\frac {\sqrt {-\sqrt {a}+\sqrt {a+b}}-\sqrt {2} \sqrt [4]{a} x}{\sqrt {\sqrt {a}+\sqrt {a+b}}}\right )}{2 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {\sqrt {a}+\sqrt {a+b}}}-\frac {\left (a+b+2 \sqrt {a} \sqrt {a+b}\right ) \tan ^{-1}\left (\frac {\sqrt {-\sqrt {a}+\sqrt {a+b}}+\sqrt {2} \sqrt [4]{a} x}{\sqrt {\sqrt {a}+\sqrt {a+b}}}\right )}{2 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {\sqrt {a}+\sqrt {a+b}}}+\frac {\left (a+b-2 \sqrt {a} \sqrt {a+b}\right ) \log \left (\sqrt {a+b}-\sqrt {2} \sqrt [4]{a} \sqrt {-\sqrt {a}+\sqrt {a+b}} x+\sqrt {a} x^2\right )}{4 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {-\sqrt {a}+\sqrt {a+b}}}-\frac {\left (a+b-2 \sqrt {a} \sqrt {a+b}\right ) \log \left (\sqrt {a+b}+\sqrt {2} \sqrt [4]{a} \sqrt {-\sqrt {a}+\sqrt {a+b}} x+\sqrt {a} x^2\right )}{4 \sqrt {2} a^{5/4} \sqrt {a+b} \sqrt {-\sqrt {a}+\sqrt {a+b}}}\\ \end {align*}
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Mathematica [C] time = 0.10, size = 164, normalized size = 0.38 \begin {gather*} -\frac {i \left (\sqrt {a}-i \sqrt {b}\right )^2 \tan ^{-1}\left (\frac {\sqrt {a} x}{\sqrt {a-i \sqrt {a} \sqrt {b}}}\right )}{2 a \sqrt {b} \sqrt {a-i \sqrt {a} \sqrt {b}}}+\frac {i \left (\sqrt {a}+i \sqrt {b}\right )^2 \tan ^{-1}\left (\frac {\sqrt {a} x}{\sqrt {a+i \sqrt {a} \sqrt {b}}}\right )}{2 a \sqrt {b} \sqrt {a+i \sqrt {a} \sqrt {b}}}+\frac {x}{a} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^4}{a+b+2 a x^2+a x^4} \, dx \end {gather*}
Verification is not applicable to the result.
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fricas [A] time = 2.05, size = 615, normalized size = 1.42 \begin {gather*} \frac {a \sqrt {\frac {a^{2} b \sqrt {-\frac {9 \, a^{2} - 6 \, a b + b^{2}}{a^{5} b}} + a - 3 \, b}{a^{2} b}} \log \left (-{\left (3 \, a^{2} + 2 \, a b - b^{2}\right )} x + {\left (a^{4} b \sqrt {-\frac {9 \, a^{2} - 6 \, a b + b^{2}}{a^{5} b}} + 3 \, a^{2} b - a b^{2}\right )} \sqrt {\frac {a^{2} b \sqrt {-\frac {9 \, a^{2} - 6 \, a b + b^{2}}{a^{5} b}} + a - 3 \, b}{a^{2} b}}\right ) - a \sqrt {\frac {a^{2} b \sqrt {-\frac {9 \, a^{2} - 6 \, a b + b^{2}}{a^{5} b}} + a - 3 \, b}{a^{2} b}} \log \left (-{\left (3 \, a^{2} + 2 \, a b - b^{2}\right )} x - {\left (a^{4} b \sqrt {-\frac {9 \, a^{2} - 6 \, a b + b^{2}}{a^{5} b}} + 3 \, a^{2} b - a b^{2}\right )} \sqrt {\frac {a^{2} b \sqrt {-\frac {9 \, a^{2} - 6 \, a b + b^{2}}{a^{5} b}} + a - 3 \, b}{a^{2} b}}\right ) - a \sqrt {-\frac {a^{2} b \sqrt {-\frac {9 \, a^{2} - 6 \, a b + b^{2}}{a^{5} b}} - a + 3 \, b}{a^{2} b}} \log \left (-{\left (3 \, a^{2} + 2 \, a b - b^{2}\right )} x + {\left (a^{4} b \sqrt {-\frac {9 \, a^{2} - 6 \, a b + b^{2}}{a^{5} b}} - 3 \, a^{2} b + a b^{2}\right )} \sqrt {-\frac {a^{2} b \sqrt {-\frac {9 \, a^{2} - 6 \, a b + b^{2}}{a^{5} b}} - a + 3 \, b}{a^{2} b}}\right ) + a \sqrt {-\frac {a^{2} b \sqrt {-\frac {9 \, a^{2} - 6 \, a b + b^{2}}{a^{5} b}} - a + 3 \, b}{a^{2} b}} \log \left (-{\left (3 \, a^{2} + 2 \, a b - b^{2}\right )} x - {\left (a^{4} b \sqrt {-\frac {9 \, a^{2} - 6 \, a b + b^{2}}{a^{5} b}} - 3 \, a^{2} b + a b^{2}\right )} \sqrt {-\frac {a^{2} b \sqrt {-\frac {9 \, a^{2} - 6 \, a b + b^{2}}{a^{5} b}} - a + 3 \, b}{a^{2} b}}\right ) + 4 \, x}{4 \, a} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.35, size = 533, normalized size = 1.23 \begin {gather*} \frac {{\left (3 \, \sqrt {a^{2} + \sqrt {-a b} a} \sqrt {-a b} a^{4} + \sqrt {a^{2} + \sqrt {-a b} a} \sqrt {-a b} a^{3} b - 4 \, \sqrt {a^{2} + \sqrt {-a b} a} \sqrt {-a b} a^{2} b^{2} + 2 \, {\left (3 \, \sqrt {a^{2} + \sqrt {-a b} a} \sqrt {-a b} a b + 4 \, \sqrt {a^{2} + \sqrt {-a b} a} \sqrt {-a b} b^{2}\right )} a^{2} - {\left (3 \, \sqrt {a^{2} + \sqrt {-a b} a} a^{3} b + 7 \, \sqrt {a^{2} + \sqrt {-a b} a} a^{2} b^{2} + 4 \, \sqrt {a^{2} + \sqrt {-a b} a} a b^{3}\right )} {\left | a \right |}\right )} \arctan \left (\frac {x}{\sqrt {\frac {a^{2} + \sqrt {a^{4} - {\left (a^{2} + a b\right )} a^{2}}}{a^{2}}}}\right )}{2 \, {\left (3 \, a^{6} b + 7 \, a^{5} b^{2} + 4 \, a^{4} b^{3}\right )}} - \frac {{\left (3 \, \sqrt {a^{2} - \sqrt {-a b} a} \sqrt {-a b} a^{4} + \sqrt {a^{2} - \sqrt {-a b} a} \sqrt {-a b} a^{3} b - 4 \, \sqrt {a^{2} - \sqrt {-a b} a} \sqrt {-a b} a^{2} b^{2} + 2 \, {\left (3 \, \sqrt {a^{2} - \sqrt {-a b} a} \sqrt {-a b} a b + 4 \, \sqrt {a^{2} - \sqrt {-a b} a} \sqrt {-a b} b^{2}\right )} a^{2} + {\left (3 \, \sqrt {a^{2} - \sqrt {-a b} a} a^{3} b + 7 \, \sqrt {a^{2} - \sqrt {-a b} a} a^{2} b^{2} + 4 \, \sqrt {a^{2} - \sqrt {-a b} a} a b^{3}\right )} {\left | a \right |}\right )} \arctan \left (\frac {x}{\sqrt {\frac {a^{2} - \sqrt {a^{4} - {\left (a^{2} + a b\right )} a^{2}}}{a^{2}}}}\right )}{2 \, {\left (3 \, a^{6} b + 7 \, a^{5} b^{2} + 4 \, a^{4} b^{3}\right )}} + \frac {x}{a} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.14, size = 1658, normalized size = 3.84
result too large to display
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \frac {x}{a} - \frac {\frac {{\left (3 \, \sqrt {a^{2} + \sqrt {-a b} a} a^{2} b + 4 \, \sqrt {a^{2} + \sqrt {-a b} a} a b^{2} - 3 \, \sqrt {a^{2} + \sqrt {-a b} a} \sqrt {-a b} a^{2} - 4 \, \sqrt {a^{2} + \sqrt {-a b} a} \sqrt {-a b} a b\right )} a \arctan \left (\frac {2 \, \sqrt {\frac {1}{2}} x}{\sqrt {\frac {2 \, a + \sqrt {-4 \, {\left (a + b\right )} a + 4 \, a^{2}}}{a}}}\right )}{2 \, {\left (3 \, a^{4} b + 4 \, a^{3} b^{2}\right )}} + \frac {{\left (3 \, \sqrt {a^{2} - \sqrt {-a b} a} a^{2} b + 4 \, \sqrt {a^{2} - \sqrt {-a b} a} a b^{2} + 3 \, \sqrt {a^{2} - \sqrt {-a b} a} \sqrt {-a b} a^{2} + 4 \, \sqrt {a^{2} - \sqrt {-a b} a} \sqrt {-a b} a b\right )} a \arctan \left (\frac {2 \, \sqrt {\frac {1}{2}} x}{\sqrt {\frac {2 \, a - \sqrt {-4 \, {\left (a + b\right )} a + 4 \, a^{2}}}{a}}}\right )}{2 \, {\left (3 \, a^{4} b + 4 \, a^{3} b^{2}\right )}}}{a} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.65, size = 1147, normalized size = 2.66 \begin {gather*} \frac {x}{a}+2\,\mathrm {atanh}\left (\frac {24\,x\,\sqrt {-a^5\,b^3}\,\sqrt {\frac {1}{16\,a\,b}-\frac {3}{16\,a^2}+\frac {3\,\sqrt {-a^5\,b^3}}{16\,a^4\,b^2}-\frac {\sqrt {-a^5\,b^3}}{16\,a^5\,b}}}{\frac {6\,\sqrt {-a^5\,b^3}}{a}+4\,a\,b^2+6\,a^2\,b-2\,b^3-\frac {2\,b^2\,\sqrt {-a^5\,b^3}}{a^3}+\frac {4\,b\,\sqrt {-a^5\,b^3}}{a^2}}-\frac {8\,x\,\sqrt {-a^5\,b^3}\,\sqrt {\frac {1}{16\,a\,b}-\frac {3}{16\,a^2}+\frac {3\,\sqrt {-a^5\,b^3}}{16\,a^4\,b^2}-\frac {\sqrt {-a^5\,b^3}}{16\,a^5\,b}}}{\frac {4\,\sqrt {-a^5\,b^3}}{a}+\frac {6\,\sqrt {-a^5\,b^3}}{b}-2\,a\,b^2+4\,a^2\,b+6\,a^3-\frac {2\,b\,\sqrt {-a^5\,b^3}}{a^2}}-\frac {8\,a\,b^2\,x\,\sqrt {\frac {1}{16\,a\,b}-\frac {3}{16\,a^2}+\frac {3\,\sqrt {-a^5\,b^3}}{16\,a^4\,b^2}-\frac {\sqrt {-a^5\,b^3}}{16\,a^5\,b}}}{4\,a\,b+\frac {4\,\sqrt {-a^5\,b^3}}{a^2}+6\,a^2-2\,b^2+\frac {6\,\sqrt {-a^5\,b^3}}{a\,b}-\frac {2\,b\,\sqrt {-a^5\,b^3}}{a^3}}+\frac {24\,a^2\,b\,x\,\sqrt {\frac {1}{16\,a\,b}-\frac {3}{16\,a^2}+\frac {3\,\sqrt {-a^5\,b^3}}{16\,a^4\,b^2}-\frac {\sqrt {-a^5\,b^3}}{16\,a^5\,b}}}{4\,a\,b+\frac {4\,\sqrt {-a^5\,b^3}}{a^2}+6\,a^2-2\,b^2+\frac {6\,\sqrt {-a^5\,b^3}}{a\,b}-\frac {2\,b\,\sqrt {-a^5\,b^3}}{a^3}}\right )\,\sqrt {\frac {3\,a\,\sqrt {-a^5\,b^3}-b\,\sqrt {-a^5\,b^3}+a^4\,b-3\,a^3\,b^2}{16\,a^5\,b^2}}+2\,\mathrm {atanh}\left (\frac {24\,x\,\sqrt {-a^5\,b^3}\,\sqrt {\frac {1}{16\,a\,b}-\frac {3}{16\,a^2}-\frac {3\,\sqrt {-a^5\,b^3}}{16\,a^4\,b^2}+\frac {\sqrt {-a^5\,b^3}}{16\,a^5\,b}}}{\frac {6\,\sqrt {-a^5\,b^3}}{a}-4\,a\,b^2-6\,a^2\,b+2\,b^3-\frac {2\,b^2\,\sqrt {-a^5\,b^3}}{a^3}+\frac {4\,b\,\sqrt {-a^5\,b^3}}{a^2}}-\frac {8\,x\,\sqrt {-a^5\,b^3}\,\sqrt {\frac {1}{16\,a\,b}-\frac {3}{16\,a^2}-\frac {3\,\sqrt {-a^5\,b^3}}{16\,a^4\,b^2}+\frac {\sqrt {-a^5\,b^3}}{16\,a^5\,b}}}{\frac {4\,\sqrt {-a^5\,b^3}}{a}+\frac {6\,\sqrt {-a^5\,b^3}}{b}+2\,a\,b^2-4\,a^2\,b-6\,a^3-\frac {2\,b\,\sqrt {-a^5\,b^3}}{a^2}}-\frac {8\,a\,b^2\,x\,\sqrt {\frac {1}{16\,a\,b}-\frac {3}{16\,a^2}-\frac {3\,\sqrt {-a^5\,b^3}}{16\,a^4\,b^2}+\frac {\sqrt {-a^5\,b^3}}{16\,a^5\,b}}}{4\,a\,b-\frac {4\,\sqrt {-a^5\,b^3}}{a^2}+6\,a^2-2\,b^2-\frac {6\,\sqrt {-a^5\,b^3}}{a\,b}+\frac {2\,b\,\sqrt {-a^5\,b^3}}{a^3}}+\frac {24\,a^2\,b\,x\,\sqrt {\frac {1}{16\,a\,b}-\frac {3}{16\,a^2}-\frac {3\,\sqrt {-a^5\,b^3}}{16\,a^4\,b^2}+\frac {\sqrt {-a^5\,b^3}}{16\,a^5\,b}}}{4\,a\,b-\frac {4\,\sqrt {-a^5\,b^3}}{a^2}+6\,a^2-2\,b^2-\frac {6\,\sqrt {-a^5\,b^3}}{a\,b}+\frac {2\,b\,\sqrt {-a^5\,b^3}}{a^3}}\right )\,\sqrt {-\frac {3\,a\,\sqrt {-a^5\,b^3}-b\,\sqrt {-a^5\,b^3}-a^4\,b+3\,a^3\,b^2}{16\,a^5\,b^2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 2.20, size = 105, normalized size = 0.24 \begin {gather*} \operatorname {RootSum} {\left (256 t^{4} a^{5} b^{2} + t^{2} \left (- 32 a^{4} b + 96 a^{3} b^{2}\right ) + a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}, \left (t \mapsto t \log {\left (x + \frac {- 64 t^{3} a^{4} b + 4 t a^{3} - 24 t a^{2} b + 4 t a b^{2}}{3 a^{2} + 2 a b - b^{2}} \right )} \right )\right )} + \frac {x}{a} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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